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2025-09-15 21:12:04 +08:00
commit 3f58f483ff
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// 使用冲突链表实现的哈希表
#ifndef LISTMAP
#define LISTMAP
#include <stdlib.h>
#include <stdio.h>
int getPri(int n) {
int primes[] = {
2, 3, 5, 7, 11, 13, 17, 19, 23, 29,
31, 37, 41, 43, 47, 53, 59, 61, 67, 71,
73, 79, 83, 89, 97, 101, 103, 107, 109, 113,
127, 131, 137, 139, 149, 151, 157, 163, 167, 173,
179, 181, 191, 193, 197, 199, 211, 223, 227, 229,
233, 239, 241, 251, 257, 263, 269, 271, 277, 281,
283, 293, 307, 311, 313, 317, 331, 337, 347, 349,
353, 359, 367, 373, 379, 383, 389, 397
};
int len = sizeof(primes) / sizeof(primes[0]);
for (int i = len - 1; i >= 0; i--) {
if (primes[i] < n) {
return primes[i];
}
}
return 1; // 如果n小于2返回1
}
typedef struct List
{
int value;
struct List *next;
}List;
typedef struct ListMap
{
int hash;
int valid;
int value;
List *next;
}ListMap;
ListMap *createListMap(int n){
int size = getPri(n);
ListMap *map = (ListMap *)malloc(sizeof(ListMap)*size);
if (map == NULL) {
printf("Error: Memory allocation failed\n");
return NULL;
}
// 初始化每个链表节点
for (int i = 0; i < size; i++) {
map[i].hash = size;
map[i].valid = 0; // 初始状态
map[i].value = 0; // 初始值
map[i].next = NULL; // 初始指针
}
return map;
}
int hashCode(int key, int hash) {
return key % hash;
}
static int get(ListMap *map, int key) {
int hash = hashCode(key, map[0].hash);
if(map[hash].valid == 0){
return -1;
}else{
if(map[hash].value == key){
return hash;
}
List *node = map[hash].next;
while (node)
{
if(node->value == key){
return hash;
}
node = node->next;
}
}
return -1;
}
int insert(ListMap *map, int key) {
int hash = hashCode(key, map[0].hash);
if(get(map, key) != -1){
return 2;
}
if(map[hash].valid == 0){
map[hash].valid = 1;
map[hash].value = key;
}else{
List *node = map[hash].next;
while (node)
{
node = node->next;
}
List *newNode = (List *)malloc(sizeof(List));
newNode->value = key;
newNode->next = NULL;
node->next = newNode;
}
return 1;
}
#endif